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x^2-58x+20=0
a = 1; b = -58; c = +20;
Δ = b2-4ac
Δ = -582-4·1·20
Δ = 3284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3284}=\sqrt{4*821}=\sqrt{4}*\sqrt{821}=2\sqrt{821}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-2\sqrt{821}}{2*1}=\frac{58-2\sqrt{821}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+2\sqrt{821}}{2*1}=\frac{58+2\sqrt{821}}{2} $
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